Harini,<div><br></div><div>The expression actor simply evaluates the expression, and places the result on the output port. So, if you have two ports (a1, a2) and the incoming value to a1 is 3 and incoming value of a2 is 5, then the expression 'a1' will output 3 on the output port, and the expression 'a1 + a2' will output 8 on the output port. See the attached figure for an illustration. Maybe I'm missing the point of your question?</div>
<div><br></div><div>Matt </div><div><br><div class="gmail_quote">On Thu, Mar 18, 2010 at 12:36 PM, <span dir="ltr"><<a href="mailto:hriyer@ncsu.edu">hriyer@ncsu.edu</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex;">
Hi,<br>
<br>
I had a query regarding the expression actor. Consider a scenario, where I<br>
have an expression actor with 2 input ports, a1 and a2, and one output<br>
port. The expression in the actor simply says a1, What is that supposed to<br>
mean? a1 and a2 given as inputs are simply some strings that represent a<br>
filename or something similar. So if the expression in the Expression<br>
actor is the name of the input port, what does that mean?<br>
<br>
Thanks,<br>
Harini<br>
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